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How to make 50% citric acid solution 03 Jun 2011 03:49 #2949

  • kalnature
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I can't seem to find info on how to make a bottle of 50% citric acid solution. Can someone tell me how much citric acid to 3oz of purified water? Thank you very much!

Aloha :)
Keiko

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Re: How to make 50% citric acid solution 03 Jun 2011 04:48 #2953

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Hi Keiko,

The best way to do it, if you have a sensitive enough scale, is to do it by weight. Then, you just use equal weights of water and citric acid powder and mix them. This will give you a 50% citric acid solution.

The other way to do it is by using equal volume amounts of both. You would want to pack the citric acid down as much as possible to remove as much air space between the crystals as possible. The problem with this second method is that because of the air spaces between the crystals, you won't have quite a 50% mix, but Jim does say that it will be close enough. I would say, just to be sure to get a little closer to the 50% mix ratio, just add an additional 5% citric acid crystal and that should get you pretty close.

When I did it by weight, I used a digital postal scale that was sensitive to 1/10 of an ounce.

Hope this helps :)

Scott
I'm Scott McRae, creator of "The Antidote" & CDH with CLO2's help (Charlotte Lackney)

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Re: How to make 50% citric acid solution 09 Jun 2011 08:29 #3077

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Thank you Scott for the information! Really appreciate it. I also was thinking about getting the Sodium Chlorite powder and mix my own. How much of Sodium Chlorite do you use to mix a 4oz bottle? Thank you again!

Aloha :)
Keiko

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Re: How to make 50% citric acid solution 25 Sep 2011 02:07 #5679

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Wait a minute...

Does 50% citric acid solution mean, 50% of VOLUME or of WEIGHT is (dry) citric acid?
While for water 50 grams equals 50 milliliters, this may or may not be so for dry citric acid crystals.
If it means by VOLUME, 50 milliliters of acid might very well be only 29 grams...

So, WHICH is it?

See also:
www.ruf.rice.edu/~bioslabs/methods/solutions/formulas.html

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Last edit: by tomcat. Reason: It clarified my point.

Re: How to make 50% citric acid solution 25 Sep 2011 05:06 #5684

  • Michael Harrah
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Hi tomcat,

It is 50% by weight to be technically correct like Scott said. However, from practical experience, 50% by volume is pretty close. With my own citric acid, it takes 50% by volume plus about another 5-10% by volume to get the weights to be even.

So, if you want to be exact, then do it by weight. If you don't have a scale, then volume is close enough to get working MMS.

Michael
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Re: How to make 50% citric acid solution 25 Sep 2011 13:37 #5696

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Hi Michael,

Thank you!
You are right, Scott did mention the weight.
Unfortunately, he also did mention "the space between the crystals" and made it sound like, once that problem is solved, one can do it by volume.
However, this is a non-problem, as one can fill in half the volume in water first and then add the crystals.
All of this left me wondering...

Greetings
Thomas

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Re: How to make 50% citric acid solution 27 Sep 2011 18:19 #5768

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Hi again,

I assume the same is true for a 28% Sodium Clorite solution?
For a total of 100 ml/grams solution I use 28 grams of the dry powder?

Thank you
Thomas

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Re: How to make 50% citric acid solution 27 Sep 2011 19:19 #5769

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Correcto. And 72 grams water...

With the 80% sodium chlorite powder (approx. 20% salt must be added to make it safe to transport and handle) as 28% of the solution, this makes the solution an actual 22.4% sodium chlorite by weight.

Bruce

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How to make 50% citric acid solution 16 Apr 2014 02:35 #43191

  • molecule
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please correct me if I'm wrong ... I'm adding this to clarify the above (for me anyway)

1. I want to finish with a 4 oz bottle of std 28% MMS (liquid volume, US oz) --

dissolve 1.6 oz NaClO2 crystals at 80% (weight, avoirdupois oz) into 4 oz pure water (liquid volume, US oz)

thus 1 lb = 16 oz (weight, avoirdupois oz) of NaClO2 (80%) will make ten 4-oz bottles finished MMS.

2. I want to finish with a 4 oz bottle (liquid volume, US oz) of 50% Citric Acid Activator --

dissolve 2.5 oz citric acid crystals at 99% (weight, avoirdupois oz) into 4 oz pure water (liquid volume US oz)

thus 25 oz (weight, avoirdupois oz) of citric acid (99%) will make ten 4-oz bottles of 50% activator solution.

3. thus, for 16 oz of NaClO2 at 80% (weight, avoirdupois oz) you need 25 oz of citric acid at 99% (weight, avoirdupois oz) to produce ten 4-oz bottles each of MMS (28%) and activator (50%)

thanks

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Last edit: by molecule. Reason: clarify activator %
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