Diluting sodium chlorite, first time

HI,
Paul and to 25% sodium chlorite without scale?

Hello Juan,
Here's another way that I've found easier, To prepare one 4 oz. bottle of 28% MMS1

1~ In a small glass bowl, put 4 level tablespoons of sodium chlorite powder.

2~ Add 3 oz. of distilled hot water.

3~ Stir with a non metalic spoon until completely dissolved. Let it sit in this glass bowl to cool for 1 hour, and then pour off the liquid into your 4 oz. bottle. Dispose of residue, if any.
~You really shouldn't have any residue left, if it was thoroughly mixed with hot, [not boiling], distilled water.

Hi alfernandes. 15ml of dry 80% sodium chlorite + 48ml water = 25% Official mms is 28% of dry 80% sodium chlorite.

Thank you Paul

Hi hobo, the tablespoons are flat?

Edit:
you sayd:

1~ In a small glass bowl, put 4 level tablespoons of sodium chlorite powder.

Sorry, didn't pay attention

Otra forma de verlo es así:

Cómo obtenemos la concentración del 22.4% que dice JIM?

utilizamos regla de tres y realizamos el siguiente ejemplo:

Si 28 grs de clorito de sodio es el 100% de producto, y su concentración es del 80% cuantos gramos de solo clorito contiene el producto adquirido?

28 --> 100% de producto total
x --> 80% concentración clorito de compra

x=22.4

Por esa razón es que al hacer la mezcla, se utiliza el 28% del clorito comprado con concentración del 80% para obtener 22.4% real.

Cosa diferente si utilizamos un clorito con un 90% de concentración. Basta aplicar la misma fórmula.

Hola luzvida


22.4/.9 = 24.888 = 25 grs de 90% clorito de sodio seca + 75 grs de aqua = 100 grs de MMS1

Paul, your numbers gives you 25% chlorite solution? Aren't wee looking for a 28% solution? maybe I didn't understand the formula

So, after reading all I come to:
Final Vol / 2.927 = Chlorite needed
Chlorite needed *2.572(thank Paul)=Water needed

so, I want 500Ml -> 500/2.927=170.823 -> 170.8gr of Chlorite
water = 170.8*2.572=439.3

so -> 500ml wanted = 170.8gr of Chlorite + 439.3gr of water

Hi, jpsala. Note that it was 90% NaClo2 instead of 80%.

28% x.8 = 22.4% pure naclo2

25% x .9 = 22.4% pure naclo2