HCl diluting

Every time I need to make a new 4 or 5% solution with muriatic acid I can't find a conversion to make a 4 ounce bottle. can anyone help me please...

Tulsaannie

I can help you but with The Information you provide i cant. I need The percent of your purchase Solution And The density or specific gravity. Also if can get The MSDS of that product will be excellent.

20° Baume Hydrochloric Acid 31.45% is that what you need? I do not know what the MSDS is... maybe www.homedepot.com/catalog/pdfImages/23/23fa0c8c-e0dc-4fa3-9aba-6aa3e7e19fd0.pdf

tulsaannie wrote: 20° Baume Hydrochloric Acid 31.45% is that what you need? I do not know what the MSDS is... maybe www.homedepot.com/catalog/pdfImages/23/23fa0c8c-e0dc-4fa3-9aba-6aa3e7e19fd0.pdf

Excellent Job! I will reply again in a few minute

tulsaannie wrote: 20° Baume Hydrochloric Acid 31.45% is that what you need? I do not know what the MSDS is... maybe www.homedepot.com/catalog/pdfImages/23/23fa0c8c-e0dc-4fa3-9aba-6aa3e7e19fd0.pdf

Ok base On The MSDS

The density is 1.16 gr/ ml. In 1 liter you have 1160 grams Of Solution that 31.45% are HCL then
364.82 are The grams of HCL. Divide By The molecular weight of HCL that is 36.45

Molarity = grams of HCL / molécule weight

364.82/36.45 = 10.0087 mol. In one liter of that Solution you have 10.0087 then

To make a 4 % Solution (w/w). You have 4 in 100 an in one liter you have 40 grams divide By molecular weight give you a 1.097 for a 4% Solution. Or 1.3717 for 5% percent.

Then The fórmula M1V1= M2V2 sustitude

4%

(10.0087)(X)=(1.097)(120ml)

X= 13.15 ml from The concentrate. Fill with distilled water to The Mark of 120 ml or 4 once.

5%

(10.0087)(X)=(1.3717)(120ml)
X= 16.44 ml. From The concentrate. Fill with distilled water to The Mark of 120 ml or 4 once

gjplaceres wrote:
Ok base On The MSDS

The density is 1.16 gr/ ml. In 1 liter you have 1160 grams Of Solution that 31.45% are HCL then
364.82 are The grams of HCL. Divide By The molecular weight of HCL that is 36.45

Molarity = grams of HCL / molécule weight

364.82/36.45 = 10.0087 mol. In one liter of that Solution you have 10.0087 then

To make a 4 % Solution (w/w). You have 4 in 100 an in one liter you have 40 grams divide By molecular weight give you a 1.097 for a 4% Solution. Or 1.3717 for 5% percent.

Then The fórmula M1V1= M2V2 sustitude

4%

(10.0087)(X)=(1.097)(120ml)

X= 13.15 ml from The concentrate. Fill with distilled water to The Mark of 120 ml or 4 once.

5%

(10.0087)(X)=(1.3717)(120ml)
X= 16.44 ml. From The concentrate. Fill with distilled water to The Mark of 120 ml or 4 once

Very important no all The HCL Solution out there are The same. Consult to The MSDS of The Cas# in The label to prepared your Solution.

my old brain can't think in ml or grams etc... I can only think in ounces etc ....but I got out my glass measuring jigger and found 15 ml and put just under that mark and filled 4 ounce bottle with distilled water... expecting it to be somewhere between 4 and 5% and I am good with that. Thanks a million!!!

Cosma, you can just use this dilution calendar, if you like..

www.restrictionmapper.org/dilutioncalc9.html

tulsaannie wrote: my old brain can't think in ml or grams etc... I can only think in ounces etc ....but I got out my glass measuring jigger and found 15 ml and put just under that mark and filled 4 ounce bottle with distilled water... expecting it to be somewhere between 4 and 5% and I am good with that. Thanks a million!!!

I dont think that precision in this Solution is very important. But be close to The amount as possible. Also only use distilled water. If you have The cup for 1 once = 30 ml fill that one with The concentrate to The Mark then add distilled water to The 1 once Mark added to your final bottle then add three more 1 once cup to that bottle.