TOPIC:

What is the difference in the grades of sodium chlorite. It seems to be a lot easier to get pure Lab grade in 99.9% or 30 % or 31% in a solution, Rather than the 80% tech grade being used. Can I use any of these to get the required concentration? regards...Jack

MMS is a (true) 22.4% of the final product. As long as you can figure out the amount of water to add to get to a 22.4% solution, you can use whatever you want. JH gives directions in his book for working with the liquid - here part of the information - from his how to make chapter

It is also possible to buy the NaClO2 in liquid form. In that case, it will
be something like 25%, 30%, or 31% NaClO2 and you will need to
dilute it with water to obtain a 22.4% solution.

and further on he writes:
So when using a liquid solution of NaClO2 bought in a barrel at any
chemical supply house for the purpose of water purification, keep in
mind that you will have to add the proper amount of distilled water to
bring it to 22.4% NaClO2.
So let’s say that you’ve bought a barrel of 31% NaClO2. Now in
a real emergency, you could just bring that home and use it as is.
Instead of using 3 drops it would be best to use 2 drops, but if lives
are at stake, don’t hesitate. For example, if someone had the swine
flu and they were spitting up blood from their lungs, that would be
enough of an emergency to make you decide to use NaClO2 from
the 31% barrel rather than spending time converting it to 22.4%. Just
use about 1/3 fewer drops than this book suggests.
On the other hand, don’t start using a 31% barrel of NaClO2 unless
there is an emergency, as you will want your MMS to have the same
results as given in this book. To sell extra-strong MMS just means
people wouldn’t be able to make it work as given in the book. It could
cause a lot of trouble. So only do this in an emergency. Otherwise
use the formulas below to convert such a barrel to 22.4% NaClO2
(MMS).

When using 80% powdered CS, then getting to 22.4%, means you use have to use 28% of the 80% (by weight) to get to 22.4% of the final product. (i.e., 28% CS, 72% water, by weight) - so, using that information, if you're using a 99% CS, then you're going to use an amount of CS that is a lot closer to 22.4% than to 28%. Looks like it will be 22.42% of your finished product. So it would be 22.42% of CS by weight, and 77,58 by weight of water.

Thanks Pam for getting back. You refer to CS that is sodium chlorite I take it. So you are saying to dilute the 99.9% ( say 100%) sodium chlorite solution down to 22.42% by adding distilled water by weight measure i.e. That is a bit less than 1 to 4. Would that also mean if water and the 99.9% solution are the same weight i.e. grams to grams, they would also be the same by volume i.e. ml to ml ?. thank you for all your efforts.....best regards....Jack

No, water and SC are not the same weight at all.

What you would do (or what I do) is take my water and measure the weight of it (and my scale is to .1 grams) - then if you are using your 99.9% SC (yes, sodium chlorite), you would go to the water and remove 22.4% of the weight of the water (you're only going to be able to get exact if you have a scale to the .01 grams) - Then add back in the sodium chlorite until you get back to the original weight of the water.

What you're looking for is SC that is 22.4% of the weight of the final solution.

I'm sure there are others that will have other ways of doing it - lots of ways to skin a cat, as they say. This is the one I learned doing the training for the minister of health course.

Thanks Pam. IF Sodium Chlorite 99.9% solution is not the same as water weight then thats OK we won't confuse the issue by bringing volume into the calculations. In the calculation of our mix are the measurements so critical or is it close enough if I consider 99.9% as 100% and 22.4% as 22.5% ? If that IS OK for our calculations you will find that 22.5% can be expressed as 9 - 40ths and that 77.5% can be expressed as 31 - 40ths. so added together is 40/40ths and to put that in practical terms and using only weight as our scale or measure. JUST AS examples : 9 Grams of SC mixed with 31 grams of water or 9 lbs SC with 31lbs of water.( that's a lot of MMS though) Of course that will only work if 22.5% can be considered as near enough to 22.4% in our calculations. Incidently The 9/40ths and 31/40ths come about when you use 2.5 as the common denominator. Dividing 22.5 by 2.5 = 9 and divide 77.5 by 2.5 =31 and 9 - 2.5s and 31 - 2.5s = 40 - 2.5s. Is there anyone who can check those calculations ?. Are my calculations close enough do you think....best regards....Jack

I can't answer these - other than to say that sc and water do not weigh the same. Thus, we don't usually measure by volume.

Maybe Steve can respond.
P

Thanks Steve. Yes I can appreciate there would be too many variables with volumes of dry Sodium chlorite. When I referred to volume I was talking only about 99 % sodium chlorite solution, sorry for any confusion. As you say some of the purer forms of Sodium chlorite solution can be a bit unstable and because there are so many different strengths or concentrations available in the solution form there would be so many variations with a few % change in the strength of the solution and we would end up spending more time in confusion about how to get the correct mix to get the proven MMS proportions and no time spent on the real issue or cause that is healing people With MMS. Yet however you arrive at it basically it's a mix of Distilled Water with 22.4%, by water weight, sodium chlorite. Promoting unsafe practices using unsafe materials would be of no help to anyone or the cause. Yes we should stick to the basic, safe and simple practices with the tried and proven ways as shown by Jim.....all the best regards....Jack

This is quite simple maths :

Dealing with a 80% grade sodium chlorite powder starter, making a 28%(w) MMS solution means 28%(w) + 72%(w) water (distilled) to make the 100% MMS solution. The (w) specify that we are dealing with a weight %. At on point I will stop writing it but it is always implied.

So : 28 g SC + 72 g water = 100% of our 28%(w) MMS solution.

The beauty with the metric system is that with pure water, by definition, volume = weight


thus our 28%(w) MMS solution = 28 g SC + 72 ml water

leading to : if 72 ml of water needs 28 g of SC, how much SC is needed for 1 liter ?


giving that a MMS solution have a 390 g/l (grams per liter) concentration. If you would have prefered to round up to 400 g/l , this would be fine since it would produce a slightly overconcentrated MMS solution of 28.57%, an overconcentration of 2% that is quite acceptable.

But since we deal with a 80% grade SC, the real SC concentration is 390 X .8 = 312 g into 1390 g of solution, giving a real 22.44%(w) SC MMS solution.

If we deal with the 400 g/l figure, this would give 400 x .8 = 320 g of real SC into a total of 1400 g solution, thus a real 22.85%(w) SC MMS solution, giving a real 1.8% overconcentrate SC MMS solution. A very acceptable error margin.

Another very useful figure to use when making MMS solutions woud be what I call the Magical Multiplicator Ratio MMR that is 1000 / 390 or 2.56 , or if you deal with the 400 g/l figure, 1000 / 400 = 2.5 .

Why this MMR ratio is usefull ? Let say you have 555 g remaining of SC powder, in what volume of water do you have to mix it in to produce your MMS solution ?

answer :
since with MMR = 2.5, we have a slightly 1.8% overconcentrated MMS solution, this allows us to round up upward the result, here 1387.5 ml to : 1400 ml giving a 28.3%(w) MMS solution.

Inversly, how many grams of SC do I have to use to make a 300 ml solution ?

answer :

To sum up :

if we have X ml of water and want to know the Y g of SC to use:


if we have Y g of sodium chlorite and want to know how much ml of water to use:


---- ---- ---- ---- ---- ---- ---- ---- ---- ----
Now, if we want to deal with another grade (concentration) of sodium chlorite powder (liquid), we have to make the following adjustments :

The 390 g/l figure (or 400 g/l), is for 80% grade SC. If we use, per instance, a 40% grade SC, we would need not 390 g but twice that amount of SC to achieve the wanted MMS solution concentration. Thus, we have to multiply 390 by the grade ratios, or 80/40 !

So, the C concentration needed for a known Z new grade (concentration) woulde be :


and your new MMR would be :



Dont forget that this is also valid for liquid sodium chlorite as long as you deal with it by weight, not volume. Only water can be dealt with by volume.


LOL

iBenny

Hi,

yes, you're right : MMR = 2.57

LOL

iBenny