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Compare cost per dose of MMS1 and CDS 11 Dec 2011 16:08 #9112

  • jemco
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Hi,

In a previous post, I inquired on how much CDS cost per dose and I just ran some quick numbers and they look quite close to MMS1.
Here's my past post:
genesis2forum.org/index.php?option=com_kunena&func=view&catid=16&id=8260&limit=6&limitstart=126&Itemid=66#8693

Ok, so this is not too complicated:

It takes 1oz of sodium chlorite (NaClO2) makes 8oz of chlorine dioxide (ClO2).
8 US fluid ounces = 236.588237 ml
Ref: www.google.com/#hl=en&cp=9&gs_id=y&xhr=t&q=8+oz+in+ml&tok=d9RneWC4cwxcN4Ca5t1KeA&pf=p&sclient=psy-ab&newwindow=1&source=hp&pbx=1&oq=8+oz+in+m&aq=0&aqi=g2g-m2&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.r_cp.,cf.osb&fp=69d31b5111065e87&biw=1366&bih=644

I am using 1ml = 1 dose of CDS.

I am also measuring a day of doses per the 1 liter bottle method of Bishop Mark and Bishop Jim.

So 8 doses of CDS per day = 8ml per day of CDS.

236 / 8 = 29.5

* That means to me that 1 oz of NaClO2 makes enough CDS for 29.5 days on protocol 1000 using CDS.

Now for the MMS1 calculations:

1 US fluid ounce = 29.5735296 ml
Ref: www.google.com/#hl=en&cp=1&gs_id=1a&xhr=t&q=1+oz+in+ml&tok=d9RneWC4cwxcN4Ca5t1KeA&pq=8+oz+in+ml&pf=p&sclient=psy-ab&newwindow=1&source=hp&pbx=1&oq=1+oz+in+ml&aq=0c&aqi=g-c4&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.r_cp.,cf.osb&fp=69d31b5111065e87&biw=1366&bih=644

Also:
1 US fluid ounce = 6 US teaspoons
Ref: www.google.com/#sclient=psy-ab&hl=en&newwindow=1&source=hp&q=1+oz+in+teaspoons&pbx=1&oq=1+oz+in+teaspoons&aq=f&aqi=g1g-m1&aql=&gs_sm=e&gs_upl=9080l10828l4l11750l9l9l0l0l0l0l560l3689l3-4.4.1l9l0&bav=on.2,or.r_gc.r_pw.r_cp.,cf.osb&fp=69d31b5111065e87&biw=1366&bih=644

Personally, I find it easy to substitute 1/4 teaspoon for my 24 drops for the day.
My citric acid drops are always bigger than the NaClO2, so it also keeps the two amounts equal.

6 teaspoons = 24 days, since there are four 1/4 teaspoons in a teaspoon and 6 * 4 = 24.

So, roughly, 1 oz of MMS1 (activated) is enough for 24 days of protocol 1000.

I know I have over simplified this a bit.

I am sure some others here can fine tune this to be more exact, but I don't think I am too far off.

Joe

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